Question

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Answer 1

\[\frac{d+3}{8d}-\frac{2d+1}{10d^2}= \frac{10d(d+3)-8(2d+1)}{80d^2}\]

Answer 2

can you solve from here?

Answer 3

Yes but how come its not 80d^2?

Answer 4

cubed I mean!

Answer 5

denominator is 80d^2

Answer 6

Yea but why is it not 80 cubed

Answer 7

\[\frac{10d(d+3)-8(2d+1)}{80d^2}\]
yes denominator is 80d^2

Answer 8

or you can write this way is the same mean
\[\frac{10d(d+3)}{80d^2}-\frac{8(2d+1)}{80d^2}\]

Answer 9

\[\frac{10d^2+30d}{80d^2}-\frac{16d+8}{80d^2}\]

Answer 10

K got it. Then i get 10d^2 +14d+8 over 80 d ^2?

Answer 11

10d^2 +14d-8 over 80 d ^2?

Answer 12

So then how would i simplify that?

Answer 13

internet problem I have restart

Answer 14

oh ok

Answer 15

let me work on my paper

Answer 16

kk

Answer 17

didision by 8 you get
internet have a problem again

Answer 18

(5d^2+7d-4): 40d^2

Answer 19

so u divided by 8?

Answer 20

yes

Answer 21

divided top and bottom by 8

Answer 22

but eight divided into 80 is 10?

Answer 23

sorry divide by 2 not 8

Answer 24

I have to go

Answer 25

k thanks but whats the final answer??

Answer 26

(5d^2+7d-4) /( 40d^2)
the final answer

Answer 27

Thanks bye