Mathematics
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OpenStudy (anonymous):
Help pretty please?
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OpenStudy (anonymous):
OpenStudy (shubhamsrg):
let x=1 and see which option matches (hit and trial) ;)
OpenStudy (shubhamsrg):
even 0 would do
OpenStudy (shubhamsrg):
altough the orthodox method would be to take 6 common from num and 5 from denom..hmm
OpenStudy (anonymous):
?
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OpenStudy (shubhamsrg):
nothing,,just put x=0 and see which option matches..
jimthompson5910 (jim_thompson5910):
What does the numerator factor to?
OpenStudy (anonymous):
I don't knoww :(
jimthompson5910 (jim_thompson5910):
What is the GCF between 6 and -18 ?
OpenStudy (anonymous):
6?
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jimthompson5910 (jim_thompson5910):
good, so 6x-18 = 6(x-3)
Do you see how I got that?
OpenStudy (anonymous):
kinda. but which corresponds to the answer choices
jimthompson5910 (jim_thompson5910):
basically if I re-distribute 6 back through, I get
6(x-3)
6*x - 6*3
6x - 18
jimthompson5910 (jim_thompson5910):
Now factor the denominator
OpenStudy (anonymous):
how
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jimthompson5910 (jim_thompson5910):
what is the GCF of 5 and -15?
OpenStudy (anonymous):
5
jimthompson5910 (jim_thompson5910):
good, so you can factor that from 5x-15 to get
5(x-3)
jimthompson5910 (jim_thompson5910):
so
\[\Large \frac{6x-18}{5x-15}\]
becomes
\[\Large \frac{6(x-3)}{5(x-3)}\]
jimthompson5910 (jim_thompson5910):
Do you see anything that cancels?
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OpenStudy (anonymous):
x-3
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
which leaves you with what?
OpenStudy (anonymous):
6 over 5
jimthompson5910 (jim_thompson5910):
you nailed it
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OpenStudy (anonymous):
Thanks ((:
jimthompson5910 (jim_thompson5910):
yw