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Mathematics 19 Online
OpenStudy (anonymous):

Help pretty please?

OpenStudy (anonymous):

OpenStudy (shubhamsrg):

let x=1 and see which option matches (hit and trial) ;)

OpenStudy (shubhamsrg):

even 0 would do

OpenStudy (shubhamsrg):

altough the orthodox method would be to take 6 common from num and 5 from denom..hmm

OpenStudy (anonymous):

?

OpenStudy (shubhamsrg):

nothing,,just put x=0 and see which option matches..

jimthompson5910 (jim_thompson5910):

What does the numerator factor to?

OpenStudy (anonymous):

I don't knoww :(

jimthompson5910 (jim_thompson5910):

What is the GCF between 6 and -18 ?

OpenStudy (anonymous):

6?

jimthompson5910 (jim_thompson5910):

good, so 6x-18 = 6(x-3) Do you see how I got that?

OpenStudy (anonymous):

kinda. but which corresponds to the answer choices

jimthompson5910 (jim_thompson5910):

basically if I re-distribute 6 back through, I get 6(x-3) 6*x - 6*3 6x - 18

jimthompson5910 (jim_thompson5910):

Now factor the denominator

OpenStudy (anonymous):

how

jimthompson5910 (jim_thompson5910):

what is the GCF of 5 and -15?

OpenStudy (anonymous):

5

jimthompson5910 (jim_thompson5910):

good, so you can factor that from 5x-15 to get 5(x-3)

jimthompson5910 (jim_thompson5910):

so \[\Large \frac{6x-18}{5x-15}\] becomes \[\Large \frac{6(x-3)}{5(x-3)}\]

jimthompson5910 (jim_thompson5910):

Do you see anything that cancels?

OpenStudy (anonymous):

x-3

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

which leaves you with what?

OpenStudy (anonymous):

6 over 5

jimthompson5910 (jim_thompson5910):

you nailed it

OpenStudy (anonymous):

Thanks ((:

jimthompson5910 (jim_thompson5910):

yw

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