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Factor completely: 3x2 + 12x + 7 Answer (3x + 1)(x + 7) (3x + 7)(x + 1) (3x + 4)(x + 3) Prime
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Choices are all wrong :| Are you sure it's the right question? because \(3x^2 + 12x + 7 \\ 3(x^2+4x)+7 \\ 3x(x+2)+7\)
I was wondering the same thing, I couldn't figure it out. Those are the correct choices and numbers, but I was thinking that it could be prime, but that doesn't work either.
Last step: \(3x(x+4)+7\); sorry.
I guess prime would be good :)
Okay, thanks!
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You are welcome :)
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