Find the quotient:
6x^3+7x^2-3x+3 / 2x+3
i had = 3x^2-x+[3/(2x+3)]
BUT on wolfram/alpha is the answer in the alternate form they give me for the answer is:
12^4+14x^3-6x^2+6x+3 / 2x
which one is correct? i am toatlly confused now on how to do these or where i went wrong please help / explain

Question

Find the quotient:  
6x^3+7x^2-3x+3 / 2x+3
i had => 3x^2-x+[3/(2x+3)]
BUT on wolfram/alpha is the answer in the alternate form they give me for the answer is:
12^4+14x^3-6x^2+6x+3 / 2x
which one is correct? i am toatlly confused now on how to do these or where i went wrong please help / explain

earthcitizen · Answer

$$(3 x^2-x)×(3+2x), r=3$$

anonymous · Answer

so then wolfram was incorrect or where do i go to see solutions or how to work out the problem?

earthcitizen · Answer

http://www.wolframalpha.com/input/?i=%286x^3%2B7x^2-3x%2B3%29+%2F%282x%2B3%29 wolfy is correct

anonymous · Answer

so the answer is according to wolfram in the alternate area is => 
12x^4+14x^3-6x^2+6x+3 / 2x

earthcitizen · Answer

we're concerned about the results not the alternative equation

anonymous · Answer

where do i find the results at i dont see it ?