Given the equation of a circle: (x + 2)^2 + (y - 7)^2 = 49 , give the center and the radius.
a.Center (2, -7); radius = 7
b.Center (-2, 7); radius = 7
c.Center (2, -7); radius = 49
d.Center (-2, 7); radius = 49

Question

Given the equation of a circle:  (x + 2)^2 + (y - 7)^2 = 49 , give the center and the radius.
	 a.Center (2, -7); radius = 7
	 b.Center (-2, 7); radius = 7
	 c.Center (2, -7); radius = 49
	 d.Center (-2, 7); radius = 49

terenzreignz · Answer

The general equation of a circle is
(x - h)^2 + (y - k)^2 = r^2, where (h,k) is the center and r is the radius
In this particular case, it seems
h = - 2 
k = 7
r = 7, 
so I'd go for
B