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Find the domain of \[f(x)=(8-3x)^{1/2}\]
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solve 8-3x>=0 and you'll get the domain
I did that but I still don't understand... I got \[(-\infty,\frac{8}{3}]\]
your answer is right :D
Oh, lol... I just realized that when I put in a number greater than 8/3... domain is so confusing.. sigh
Thanks so much for you help once again!
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What would I do if that was x^2?
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