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Mathematics 11 Online
OpenStudy (anonymous):

Factor this expression completely and then place the factors in the proper location on the grid. 36y2 - 1

mathslover (mathslover):

\[\Huge{(6y)^2-(1)^2}\] \[\Huge{(6y+1)(6y-1)}\] DO remember the identity that i applied here : \[\Huge{a^2-b^2=(a+b)(a-b)}\]

OpenStudy (anonymous):

Thanks!

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