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Mathematics 21 Online
OpenStudy (anonymous):

Calculate {4-9i}

mathslover (mathslover):

\[\Huge{4-9i}\] \[\Huge{(2)^2-(3\sqrt{i})^2}\] \[\Huge{(2+3\sqrt{i})(2-3\sqrt{i})}\]

mathslover (mathslover):

his can be simplified like this not .calculated ... if u want still to then put i =\(\Huge\sqrt{-1}\)

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