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Im working on this problem: 9. Differentiate H(z) = 2^1-6z
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d(2)-d(6z)
d(2) is 0, right?
yes
-6 is the answer
No its not. The answer is -6(1-6z) ln(2).
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But I have no idea why there is a natural log.
http://www.wolframalpha.com/input/?i=%20Differentiate%20%20H(z)%20%3D%202%5E1-6z&t=crmtb01
i am right according to wolfram alpha ...see steps
Maybe I should have typed H(z) = 2^(1-6z)
check that what is the correct ans.
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http://www.wolframalpha.com/input/?i=differentiate+H%28z%29+%3D+2%5E%281-6z%29
this was my fault for not writing the problem correctly
ok ... so u got the correct answer ?
Yes.
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