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Mathematics 19 Online
OpenStudy (anonymous):

Solve. x2 + 5x = –6

OpenStudy (anonymous):

is it 2x+5x=-6? Then it would be -6/7=x

mathslover (mathslover):

\[\Huge{x^2+5x+6=0}\] \[\Huge{x^2+3x+2x+6=0}\] \[\Huge{x(x+3)+2(x+3)=0}\] \[\Huge{(x+2)(x+3)=0}\]

OpenStudy (anonymous):

it's x^2+ 5x = –6

OpenStudy (earthcitizen):

re-arrange\[x^2+5 x+6 = 0\] use quadratic formula \[x = (-b \pm \sqrt{b^{2} - 4ac})/2a \therefore ax^{2} + bx +c = 0\] a = 1, b =5 and c= 6 then sbst

OpenStudy (anonymous):

x = 5 and x = 1 x = –5 and x = –1 x = 3 and x = 2 x = –3 and x = –2 HELP

OpenStudy (earthcitizen):

x = -3 ,-2

OpenStudy (anonymous):

Thank you

OpenStudy (earthcitizen):

yw

OpenStudy (anonymous):

x=-6

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