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If y=2x^3+6x and dx/dt = 6, find dy/dx when x=5 .
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\[y^{'} (x) = 6x^{2} + 6 \] at x = 5, subst all x for 5
thats not an answer choice
all the answers and in the 900s
hmmm.. i'm with earthcitizen.... the answer is not 156?
is y a function of t?
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there is one that says none of these i can try that
or x?
x
is dy/dx = (dy/dt)*(dt/dx)
dont think so
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i don't see any relationship wiv dx/dt and dy/dx
i agree with earthcitizen again... there has to be some relationship between y and t.
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