Question

6a^2x(9a^2+4bcx^2+6abx

Answer 1

1) distribute 6a^2x to each of the monomials
2) your work would look like (6a^2x)(9a^2)+(6a^2x)(4bcx^2)+(6a^2x)(6abx)
3) then your answer would be 54a^4x+24abcx^4x+36bx^4x

hope that helps :D