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Mathematics 25 Online
OpenStudy (anonymous):

Factor completely. ay 2 + 2ay - 3a

OpenStudy (anonymous):

Take a common first: \[a(y^2 + 2y - 3)\] Now make factors, \[a(y^2 + 3y - y -3) = a(y +3)((y-1)\] is the answer..

OpenStudy (anonymous):

Thank You :)

OpenStudy (anonymous):

Welcome dear..

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