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\[cosx=\frac{adjacent}{hypotenuse}\] \[cos30=\frac{5\sqrt3}{z}\] \[\frac{\sqrt3}{2}=\frac{5\sqrt3}{z}\] Can u solve nw?
no :\
\[z=\frac{5\sqrt3*2}{\sqrt3}\] vat abt nw?
\[Z=5\sqrt{3}\text{ Sec}[30{}^{\circ}]=10\]
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