Question

solve for x

Answer 1

\[\sqrt{12} (\sqrt{3 } - x ) = 15\]

Answer 2

\[\sqrt{36}-x\sqrt{12}=15\]
\[6-2x\sqrt{3}=15\]
\[-2x\sqrt{3}=9\]
\[x=-9/2\sqrt{3}=-9\sqrt{3}/6=-3\sqrt{3}/2\]

Answer 3

in \[-9 \sqrt{3} /6\] where did the 6 came from? :S

Answer 4

sqrt3sqrt3 *2 =6

Answer 5

rationalizing the denominator

Answer 6

multiplyed top and bottom by sqrt3

Answer 7

thanks :)

Answer 8

yw