Question

working on a problem, stuck on the algebra..
[-8*(3x+2)^3/(4x+3)^2]+[9*(3x+2)^2/(4x+3)^2]

how do i reduce that??
*Been playing around with wolfarm, thought about a^3/b^3 + a^2/b^2..a^2(a+b)/b^3
not sure if that is right, not sure how its doing that
thanks!!

Answer 1

a^3/b^2 + a^2/b^2
((a^3b^2)+(a^2b^2))/(b^4)
b^2((a^3)+(a^2))/(b^4)
((a^3)+(a^2))/(b^2)
(-8(3x+2)^3 + 9(3x+2)^2)/(4x+3)^2
(-8(27x^3 + 54x^2 + 36x + 8) + 9(27x^3 + 54x^2 + 36x + 8))/(16x^2+24x+9)
((-216x^3 - 432x^2 - 288x - 64) + (243x^3 + 486x^2 + 324x + 72))/(16x^2+24x+9)
(27x^3 + 54x^2 - 36x + 9)/ (16x^2+24x+9)
9(3x^3 + 6x^2 - 4x + 1)/(16x^2+24x+9)
9(3x^3 + 6x^2 - 4x + 1)/((4x+3)(4x+3))
Not sure what to do with the top.

Answer 2

thanks!!