Question

y varies directly as the square of x. When x = 5, y = 5. Find y when x = 10.

Answer 1

is y=(1/5)*x*x
if x=10 y=20

Answer 2

how did you get that?

Answer 3

use y= kx2 and after putting for x=5 and y=5 we have k=1/5

Answer 4

y α x^2
y/x^2 = k
\[\frac{y_1}{x_1\ ^2} = \frac{y_2}{x_2\ ^2}\]Put \(x_1=5, y_1=5\) and \(x_2 = 10\)into it.
\[\frac{5}{5^2} = \frac{y}{10^2}\]\[\frac{1}{5} = \frac{y}{100}\]Solve y.

Answer 5

oh wow that makes alot of sense thanks

Answer 6

Welcome!