Question

Find the vertex of the parabola by completing the square.
x2-6x+8=y
(the x is squared)


A. (–3,– 6)

B. (3,–1)

C. (–3,1)

D. (–1, 3)

Answer 1

(x-h)^2+k has a vertex of (h,k)

x^2-6x+8=y
x2-6x =y-8
x^2-6x+9=y-8+9
(x-3)^2=y+1
(x-3)^2-1=y

Vertex is (3,-1)