Question

Help!!!!!!
Solve for x :
2log(base3) x-2 + 2log(base3) x-4 = 0

Answer 1

x-2=(1/(x-4))
solve to get x

Answer 2

\[2\log_{3} x-2 + 2\log_{3}x-4 = 0\]

Answer 3

answer please!!!!!!!!

Answer 4

no buddy,,.you solve please..i mean try yourself..we may correct you whenever required..

Answer 5

is (x-2)(x-4)=1 the answer?

Answer 6

Ans. 3+root2 , 3

Answer 7

x^2-6x+7=0

Answer 8

hey nitz have you posted only x^2 - 6x +7 = 0

Answer 9

because i am not able to see any other thing here.