what is the standard form of Ellipse with foci at (4, 2) and (10, 2) and co-vertices at (7, 0) and (7, 4)

Question

what is the standard form of Ellipse with foci at (4, 2) and (10, 2) and co-vertices at  (7, 0) and (7, 4)

anonymous · Answer

The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2, the fraction is now equal to 2/3.

If n = the numerator and d = the denominator, which of the following systems of equations could be used to solve the problem?

5n = 3d and 3n + 6 = 2d + 4
5n = 3d and 4n + 4 = 3d + 6
3n = 5d and 3n + 6 = 2d + 4

anonymous · Answer

JOHN SHUT UP

anonymous · Answer

an how do uknow my name

anonymous · Answer

ok honey so the center is 7,2 becuz it is the midpoint of the foci. now we kno that its ellipse so c^2 = a^2 - b^2 so just plug and chug baby. so c we kno is 3 and b is 2 so we get 9 = a^2 - 4, then we get a = plug or minus sqrt of 13. so the final answer is :

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