Question

What is the simplified version of 3 log x + log y + log z ? help pleasee

Answer 1

log (x^m)=mlogx
log(m)+log(n)=log(mn)
log(m)-log(n)=log (m/n)
3logx=log(x^3) and -logy-logz=-(logy+logz)=-log(yz)
3logx-logy-logz=log(x^3)-log(yz)
=log(x^3/yz)

Answer 2

use the logarithms property :
log m + log n = log(mn)

Answer 3

thankss