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The length of the diagonal of a square is 8 inches. What is the area of the square?
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If the length of a side of a squre is 'a' then diagonal's length=\[a \sqrt{2}.\] so side= diagonal/sqrt{2} So area = (side)^2= (diagonal/sqrt{2})^2.
area=\[(\frac{diagonal}{\sqrt{2}})^2.\]
so the answer is 32 ?
yeah well done:)
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