Question

what are the possible number of positive, negative, and complex zeros of f(x)= -2x^3 - 5x^2 - 6x +4? Use complete sentences to ecplain the method used to solve this equation.


Thank you!!!!!

Answer 1

ever heard of descartes rule of signs ?

Answer 2

descartes' ** :P

Answer 3

Yes, but I still do not understand

Answer 4

well,,for f(+x),,we see only 1 change in sign..so 1 +ve root
for f(-x),,2 changes in signs,,so 2 -ve roots..
thus no complex roots (since degree is 3 and we already have 3 roots)

NOTE : these are just possible roots

Answer 5

hope it helped

Answer 6

THANK YOU!!!

Answer 7

glad to help ^_^