Question

help me
$6,000 dollars is invested in two different accounts earning 3% and 5% interest. At the end of one year, the two accounts earned $220 in interest. How much money was invested at 3%?

$2,000
$3,000
$4,000

Answer 1

lets say,
amount invested in first account x
amount invested in second account y

x + y = 6000

Answer 2

interest on x = 3% = .03x
interest on y = 5% = .05y

since, total interest earned is 220

.03x + .05y = 220
3x + 5y = 22000

Answer 3

so, we got two equations :
x + y = 6000
3x + 2y = 22000

Answer 4

can you solve for x now ?

Answer 5

i had got 2000

Answer 6

wait a sec. . let me check

Answer 7

i am getting 4000 in first account(account with 3% interest rate)
& 2000 in second account.

Answer 8

so was i right

Answer 9

nope
$4000 is the answer

Answer 10

ook thx

Answer 11

yw