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Solve for x. -5|x + 1| = -10
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Isolate the absolute value; \(|x+1|=-10\div-5\\ |x+1|=2\)
Now, we know that the absolute value of something absolutely give some positive number; |5|=5 AND |-5|=5 Therefore we can conclude that things between | | can take two different value; in this case, 2( 2 and -2)
Now let's set up our final step, build up two equations to solve x So, |2|=2; |-2|=2 Therefore solve x for \(x+1=2;~x+1=-2\)
\(x+1=2\\ x=2-1\\x=1\) \(x+1=-2\\ x=-2-1\\ x=-3\)
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