Question

what is an equation of the line that passes through the point (3, -8) and has the slope -2?

Answer 1

equation of the line is given by (y-y1)=m(x-x1) ,
where 'm' is the slope and (x1,y1) is the point through which the line passes
so we get...
y+8=-2(x-3)
on solving,we get
2x+y+2=0