Question

y varies directly as the square of x. When x = 3, y = 18. What is the value of y when x = 4?

Answer 1

y = kx^2 where k = constant
x = 3, y = 18
18 = k* 3^2
so k = 18/9 = 2

so the relation is y = 2x^2

so plug in x=4 into this formula and you'll get value of y

Answer 2

thanks

Answer 3

yw