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Give the standard form of the equation. Hyperbola with vertex at (0, 4), focus at (0, 5), and center at (0, 1)
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a^2+b^2=c^2 c=5 and a=4
can u give it to me in this form.
That's why I showed you how to find a, b, and c so you could write it in that form.
\[\frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1\]
\[\frac{(y-1)^2)}{16}-\frac{(x-0)^2}{9}=1\]
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