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what is the area, in square millieters, of a right triangle with a hypotenuse of 68 millimeters and leg of 60 millimeters? a. 2,040 mm^2 b. 1,920 mm^2 c. 1,088 mm^2 d. 960 mm^2
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find length of the other leg using pythagoras = sqrt(68^2 - 60^2) then the area = 0.5 * 60 * this value
30...?
what - the other leg - pretty close
so area = 30 * length of other leg
sqrt (1024)
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- thats the other leg
ok
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