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Help solve please. 5(-3)+2(2+x)=>17
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I messed up. let me re-write it.
ah ok
5(x-3)+2(2+x)=>17 Sorry about that.
distribute you get this 0 <= 7*x-28 can you do that?
Can you show me how you got that?, I don't understand.
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|dw:1340234867180:dw|
5(x-3)+2(2+x)=>17 \(\large 5(x-3)+2(2+x)\ge17 \) \(\large 15x-15+4+2x\ge17 \) \(\large 15x+2x-15+4\ge17 \) \(\large 17x-11\ge17 \) \(\large 17x-11+11\ge17+11 \) \(\large 17x\ge28 \) \(\large x\ge \frac{28}{17} \)
Thank you so much dpalnc :D
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