Question

solve the system of linear equation with the elimination method:
2x+y=1
3x+6y+30

Answer 1

2x+y=1 <=> -12x-6y=-6 add that to the second equation
3x-12x-6y+6y+30=0 <=>(eliminate y) => -9x+30=0 => x=10/3
Plug that x in the first equation, 20/3+y=1 => y=-17/3

Answer 2

2x+y=1 ..........eq(1)
3x+6y+30.............eq(2)
multiply eq(1) by 3 and eq(2) by 2 then u wll get
6x+3y=3 ..........eq(3)
6x+12y=60 ..........eq(4)
then subtract eq(3) from eq(4)..then 6x will cancel 6x then left with
9y=57
y =57/9
then take y and replace @ eq(1) u will get....
2x=1-(57/3)
then divide both sides by 2.... u will get
x=(1-(57/3))/2