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Simplify i ^6 • i^8.
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Also, these represent Imaginary Numbers. ( The "i"s
Same base Since multiplying add exponents \[i^{14}=(i^2)^7\] ---- What is \[i^2=?\]
i*i?
hum - i find these tricky by definition i^2 = -1
so its (-1)^7
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Thats my final answer?
My choices state i -1 -i 1
no -1*-1*-1*-1*-1*-1*-1 = 1 * 1 * 1 * -1 = -1
Oh, i have the actually square it by 7... hmk. Thanks~!
of you remember that i^2 = -1 you can do these easily also you can remember that i^4 = 1 so foe example i^5 =i^4 * i = 1 * i = i
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