Question

x^3-4x^2>0

Answer 1

See, when we carry a term from one side to other side then we do exactly opposite of it..
Let me explain:
x - 3 = 2x - 4

If I want to carry 3 on other side then,
Here 3 is negative, then on carrying other side it will become positive..
x = 2x - 4 +3

Got or not??
Similarly,
+ becomes - on other side,
- becomes + on other side,
* becomes / on other side,
/ becomes * on other side...

Answer 2

So, here if you want that -4x^2 should be carried to other side, then what you will do @kman1357 ??

Answer 3

@waterineyes divide -4?

Answer 4

No buddy,
It is a negative term and how negative term is carried to other side, I have just said above,

Now to carry a negative (-) term, what will you do @kman1357 ???

Answer 5

@waterineyes switch signs?idk math is my low spot...

Answer 6

If by switching you mean positive then you are right..
-4x^2 will go to right hand and its sign changes to +..

So, above equation will become :
x^3 > 4x^2

Getting or not??

Answer 7

a little is that the answer?

Answer 8

Buddy cool down,
we have to find the value of x..
Now what do you think what is cancelling out there???

Answer 9

no i dont ok!

Answer 10

Rewrite the equation:
\[x^{3}-4x^{2} > 0\]
\[x*x*x-4(x*x) > 0\]
\[x*(x*x)-4(x*x) > 0\]

Since AB + AC is the same thing as A(B + C), do the same to what's above.

Answer 11

@Wired huh?

Answer 12

Compare them to each other. In this case, both parts have (X*X) in common. That's A. B is the X on the left, C is -4 on the right.

Answer 13

@wired but i need an answer im timied right now

Answer 14

What is the profit if you only require the answer and not the solution how to reach at that answer...???

Answer 15

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