Question

Find all solutions of the system of equations.


x − 2y = 3
y2 − x2 = 3x + 9

Answer 1

put x=3+2y in second equation

Answer 2

what about that x being squared?

Answer 3

wait

Answer 4

see i am telling you that from first equation, we get x=3+2y
put this value of x in second equation

Answer 5

x. not the x ^2?

Answer 6

mam second equation is having x^2

Answer 7

is it y^2-x^2=3x+9 the second equation

Answer 8

?????????

Answer 9

im writing

Answer 10

y^2-(2y+3)(2y+3)=3(2y+3)+9?

Answer 11

y^2-(2y+3)^2=3(2y+3)+9
(y-(2y+3))(y+(2y+3))=6y+9+9
(-y-3)(3y+3)=6y+18

Answer 12

ok till here????????

Answer 13

yes :)

Answer 14

-(y+3)(3y+3)=6y+18
-(y+3)3(y+1)=3(2y+6)
cancel 3 on both sides
-(y+3)(y+1)=2y+6

Answer 15

-(y^2+4y+3)=2y+6
-y^2-4y-3=2y+6
-y^2-4y-2y-3-6=0
-y^2-6y-9=0
-(y^2+6y+9)=0
therefore,y^2+6y+9=0
(y+3)^2=0
so,y=-3,-3

Answer 16

yes or no?????

Answer 17

yes

Answer 18

so put y=-3 in x=3+2y
x=3+2(-3)
x=3-6
x=-3
so,(-3,-3) is the solution set

Answer 19

fine emily.......

Answer 20

ya got or not? you can ask wherever you have doubt?

Answer 21

Thank you, sorry i had someone at the door . Thank you for your help :)

Answer 22

you are always welcome.......any other question?

Answer 23

nope, thats all for now thank you