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how to factorise x^2-3x-4?
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\[x^2-3x-4=0\] Find two numbers that multiply to be -4 and add to be -3, and those are the solutions you need to answer.
oduct sum rule Product=-4 Sum=1 =x^2+x-4x-4=0 =x(x+1)-4(x+1)=0 =(x-4)(x+1) (x-4) =0 & (x+1)=0 ans x=4 or x=-1
@AfricanBrucelee cannot be,cuz this question comes from a partial fraction question and whe i used the values you gave me the answer didn't work out
(x+1)(x-4)=0->x=-1,x=4
@Syderitic That seems legit. thanks man!
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good then i'll attempt using another method.......
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