Question

cscӨcotӨ/secӨ= a)1 b) csc^Ө c)cot^2Ө d)sec^2Ө

Answer 1

what is this? cscӨ???? = cosecӨ

Answer 2

c)cot^2Ө

Answer 3

\[(\cos \theta)(\cos \theta) /(\sin \theta)(\sin \theta)\]

Answer 4

\[\cot \theta = \cos \theta /\sin \theta\]

\[cosec \theta = 1/\sin \theta \]

\[1/\sec \theta = \cos \theta \]

Put this in the question:

You will reach your answer...

Answer 5

thanks again! that's all for tonight

Answer 6

so \[\cos ^{2}\theta/\sin ^{2}\theta=\cot ^{2}\theta \]