If the perimeter of the triangle below is 41, find the value of x.
http://roads.advancedacademics.com/contentserver/content/roadssection/279461/questions/assessments/t-perimeterareatrianglesquiz/geometry_unit4_5_quiz_8q.gif

Question

If the perimeter of the triangle below is 41, find the value of x.
http://roads.advancedacademics.com/contentserver/content/roadssection/279461/questions/assessments/t-perimeterareatrianglesquiz/geometry_unit4_5_quiz_8q.gif

pfenn1 · Answer

The perimeter equals the sum of the sides. Write an equation where you add up all the lengths of the sides to equal 41, then solve for x.

pfenn1 · Answer

$$3x+(5x+2)+(6x-3)=41$$Solve for x.

anonymous · Answer

THANKS

anonymous · Answer

$$Here, (5x + 2) + (6x-3)+3x = 41$$
$$14x - 1 = 41 => 14x = 42 => x=3$$

anonymous · Answer

OH OKAY because i was doing it in another way

pfenn1 · Answer

You're welcome.