Question

In △PQR, QS is an altitude.



Solve for x and y.

Answer 1

okay this is hard lol

Answer 2

yes it is really hard

Answer 3

For triangle PQR=>
Using pythagoras theorem
y^2+z^2=(25)^2
z^2=(25)^2-y^2
For triangle QSR=>
x^2+5^2=z^2
x^2+5^2=25^2-y^2
x^2=25^2-5^2-y^2
For triangle PSQ=>
20^2+x^2=y^2
x^2=y^2-20^2-(1)
25^2-5^2-y^2=y^2-20^2
625-25=y^2+y^2-400
2y^2=600+400
solve for y.
Then substitute the value of y in (1) to find x.
Can u do?