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The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference. 8/9 1.8 2
a10 = a+9d 13 = (-5)+9d 13+5 = 9d 18 = 9d 18/9 = d 2 = d
common difference is 2
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just give the question i'll try to solve...
okey here it is Find the 31st term of the following sequence. 9, 15, 21, ... 186 189 195
a31 = a+30d here a=9 & d=6 therefore, a31 = 9+30x6 a31 = 9+180 a31=189
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