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If we toss three coins 120 times, how many times can we expect the coins to have exactly one head showing? 15 30 60 45
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Expected Value = n*p Find the probability of getting 1 heads with 3 coins tossed and multiply it by 120
would that get me 60 then ?
HTT THT TTH that's 3 out of 2^3 total possibilities
\[\Large = 120 \times \frac38\]
45?
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