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Mathematics 11 Online
OpenStudy (anonymous):

is this correct? prob. factor completely=> 20x^2 + 100x + 125 my answer is=> 4x^2+10+25

OpenStudy (anonymous):

4x^2+25x+25 (4x+5)(x+5)

OpenStudy (anonymous):

oh would the factor be 5?

OpenStudy (anonymous):

yes. i guess i assumed it all was equal to zero. really should be 5(4x+5)(x+5)

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