Mathematics
7 Online
OpenStudy (anonymous):
x^2=6x+27
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myininaya (myininaya):
Put everything on one side.
myininaya (myininaya):
Let me know when you have done that
OpenStudy (anonymous):
x^2-6x+27
myininaya (myininaya):
almost you did to subtract 27 on both sides
myininaya (myininaya):
\[x^2-6x-27=0\]
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myininaya (myininaya):
Can you factor here?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
x^2-1+3
myininaya (myininaya):
no...
What are two factors of -27 that have product -27 and sum -6 ?
OpenStudy (anonymous):
-3, 9
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myininaya (myininaya):
does -3+9 add up to be -6?
or does 3+(-9) add up to be -6?
OpenStudy (anonymous):
3+(-9)
myininaya (myininaya):
ok so the factors are (x+3)(x-9)
So can you solve this equation now (x+3)(x-9)=0
OpenStudy (anonymous):
(x+3) (x-9)
myininaya (myininaya):
Set both of those factors =0
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myininaya (myininaya):
x+3=0
x-9=0
myininaya (myininaya):
Solve both equations and you are done
OpenStudy (anonymous):
3, 9
myininaya (myininaya):
Trying solve that first equation again
OpenStudy (anonymous):
0,9
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myininaya (myininaya):
x+3=0
How do you solve this?
How do you get x by itself?
OpenStudy (anonymous):
subtract from both sides
myininaya (myininaya):
Subract what from both sides?
OpenStudy (anonymous):
3
myininaya (myininaya):
Yes you are subtracting 3 on both sides
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myininaya (myininaya):
so you have x+3=0
-3 -3
x=-3
myininaya (myininaya):
sO your solutions are?
OpenStudy (anonymous):
-3,9
myininaya (myininaya):
Yes :)
OpenStudy (anonymous):
Thnak you!!!!!!