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Mathematics 7 Online
OpenStudy (anonymous):

x^2=6x+27

myininaya (myininaya):

Put everything on one side.

myininaya (myininaya):

Let me know when you have done that

OpenStudy (anonymous):

x^2-6x+27

myininaya (myininaya):

almost you did to subtract 27 on both sides

myininaya (myininaya):

\[x^2-6x-27=0\]

myininaya (myininaya):

Can you factor here?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

x^2-1+3

myininaya (myininaya):

no... What are two factors of -27 that have product -27 and sum -6 ?

OpenStudy (anonymous):

-3, 9

myininaya (myininaya):

does -3+9 add up to be -6? or does 3+(-9) add up to be -6?

OpenStudy (anonymous):

3+(-9)

myininaya (myininaya):

ok so the factors are (x+3)(x-9) So can you solve this equation now (x+3)(x-9)=0

OpenStudy (anonymous):

(x+3) (x-9)

myininaya (myininaya):

Set both of those factors =0

myininaya (myininaya):

x+3=0 x-9=0

myininaya (myininaya):

Solve both equations and you are done

OpenStudy (anonymous):

3, 9

myininaya (myininaya):

Trying solve that first equation again

OpenStudy (anonymous):

0,9

myininaya (myininaya):

x+3=0 How do you solve this? How do you get x by itself?

OpenStudy (anonymous):

subtract from both sides

myininaya (myininaya):

Subract what from both sides?

OpenStudy (anonymous):

3

myininaya (myininaya):

Yes you are subtracting 3 on both sides

myininaya (myininaya):

so you have x+3=0 -3 -3 x=-3

myininaya (myininaya):

sO your solutions are?

OpenStudy (anonymous):

-3,9

myininaya (myininaya):

Yes :)

OpenStudy (anonymous):

Thnak you!!!!!!

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