The slope is -2 and the line passes through (4,-5). what is the equation?
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OpenStudy (anonymous):
y=-2x+3
OpenStudy (anonymous):
Not really. These things are the hardest for me.
OpenStudy (anonymous):
do you know how to do that?
OpenStudy (anonymous):
first you have to identify this as a direct line,
in general we write it as y=mx+c
where m is the slope and c is the intercept.
m=-2 is given.apply the point (4,-5) which will give you the c.
OpenStudy (anonymous):
y=-2x+3 where do the 4 and -5 go?
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OpenStudy (anonymous):
since you know the slope (m=-2) apply it,
y=-2x+c
to get the c apply (4,-5),that is x=4 and y=-5
OpenStudy (anonymous):
Oh. Ok.
OpenStudy (anonymous):
:-)
OpenStudy (anonymous):
Wait, im confused.
OpenStudy (anonymous):
so that would be -5=-2(4)+c ??
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
how do you get that to y=2x+3 ?
OpenStudy (anonymous):
-5=-2(4)+c
solve this you yeild c=3
so now you have everything for your direct line,
y=-2x+3
OpenStudy (anonymous):
so my next problem is Slope= 2/5 and line passes through (2,1/2)
OpenStudy (anonymous):
so -1/2=2/5(2)+c ??
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OpenStudy (anonymous):
same as above,yes you are correct but y should be 1/2.
OpenStudy (anonymous):
sorry i wrote it wrong. (2,-1/2)
OpenStudy (anonymous):
then you applied it correctly :-)
OpenStudy (anonymous):
now im just confused with solving. especially with fractions
OpenStudy (anonymous):
why don't you use a calculator?
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