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Mathematics 12 Online
OpenStudy (anonymous):

Y varies jointly as A and B and inversely as the square root of C. Y=16 when A =4, B=4 and C=4. find Y when A=6, B=3 and C=16 Y=__

OpenStudy (dumbcow):

Y = k*(AB)/sqrtC , where k is a constant plug in values to solve for constant 16 = 16k/sqrt(4) 16 = 8k k = 2 --> Y = (2*6*3)/sqrt(16) --> Y = 36/4 --> Y = 9

OpenStudy (anonymous):

wow most detail answer i have gotten yet thanks

OpenStudy (dumbcow):

your welcome...glad to help

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