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OpenStudy (anonymous):
Y varies jointly as A and B and inversely as the square root of C. Y=16 when A =4, B=4 and C=4. find Y when A=6, B=3 and C=16 Y=__
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OpenStudy (dumbcow):
Y = k*(AB)/sqrtC , where k is a constant plug in values to solve for constant 16 = 16k/sqrt(4) 16 = 8k k = 2 --> Y = (2*6*3)/sqrt(16) --> Y = 36/4 --> Y = 9
OpenStudy (anonymous):
wow most detail answer i have gotten yet thanks
OpenStudy (dumbcow):
your welcome...glad to help
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