The sum of the measures of the interior angles of a polygon is five times the sum of the measures of its exterior angles, one angle at each vertex. How many sides does the polygon have?
*can someone help me and explain the answer to me world problems are a struggle.

Question

The sum of the measures of the interior angles of a polygon is five times the sum of the measures of its exterior angles, one angle at each vertex. How many sides does the polygon have?
*can someone help me and explain the answer to me world problems are a struggle.

paxpolaris · Answer

What is the sum of the measures of its exterior angles?

paxpolaris · Answer

What is the sum of the measures of exterior angles of ANY polygon?

anonymous · Answer

Since the sum of the exterior angles of a polygon is always 360, the sum of the interior angles is 1800. Further, the sum of the interior angles of a polygon is (n-2)180.
(n-2)180 = 1800
n-2 = 10
n = 12

anonymous · Answer

thank you :)