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factor. 3x^2-5x-12
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try to find those 2no. which has a product=3*12=36, and have a difference between them=5. we have, 36=1*36 36=2*18 36=3*12 36=4*9 ----------->here, we have a difference of 5 between the no.(irrespective of signs) \[3x^{2}-5x-12\] \[3x^{2}-9x+4x-12\] (writing -5 as sum of -9 and 4) Take out common value from any two groups \[[3x^{2}-9x][+4x-12]\] \[3x(x-3)3(+x-3)\] =\[(3x+3)(x-3)\]
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