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Mathematics 20 Online
OpenStudy (anonymous):

original problem x + y = 5 x = 4y x =4y x +y = 5 (4y) + y =5 because we substitute 4y for x Then add 4y and y 5y = 5 Divide both sides by 5 to get the y alone 5y/5 = 5/5 5/5=1 y=1 Then i put in the second equation x=4(1) 4x1=4 so x=4 and y =1 i need checksteps for both problems please

OpenStudy (precal):

so you need to check to see if x=4 and y=1, is that correct?

OpenStudy (precal):

|dw:1340335533536:dw| yes it is the solution

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