Question

simplify 125^-2/3

Answer 1

\[a^2=a \times a\]\[a^{-2}=\frac{1}{a^2}=\frac{1}{a \times a}\]\[a^{\frac{1}{2}}=\sqrt{a}.\]\[a^{\frac{1}{3}}=\sqrt[3]{a}\]So; \[125^{\frac{-2}{3}}=\sqrt[3]{\frac{1}{125^2}}\]

Answer 2

\[\implies \sqrt[3]{\frac{1}{5*5*5*5*5*5}}\]Now do this

Answer 3

tell me what do u get?

Answer 4

15625 :o for all thee 5x5x5 etc

Answer 5

no i don't want ur calculation
I want the cube root of that big problem only looking big

Answer 6

625?

Answer 7

no try once again but remember
take cuberoot of numerator & denominator separately