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1) add 3 2) divide by 6 3) square 4) subtract 1
Let \[\sqrt{x+1}\]=A So ur question will look like\[6A-3=15.\] So; A=3 It means \[\sqrt{x+1}=A=3\]
Is it the 6th root of x+1 or 6√x+1 ?? :/
A, x = 107 B, x = 8 C, x = 75 D, x = 71
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B. X=8
From my solution; \[A=\sqrt{x+1}=3 \implies x+1=9 \implies x=8.\]
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