Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

6ab-6ac+6b^2-6bc... Factor this expression...

OpenStudy (agent47):

easy.. first of all pull out a 6: 6(ab-ac+b^2-bc)

Parth (parthkohli):

Do it by grouping \( \color{Black}{\Rightarrow 6a(b - c) + 6b(b - c)}\) \( \color{Black}{\Rightarrow (6a + 6b)(b - c)}\)

Parth (parthkohli):

\( \color{Black}{\Rightarrow 6(a + b)(b - c)}\)

OpenStudy (anonymous):

i got it wrong but it was 25%

OpenStudy (agent47):

Parth is brilliant!

Parth (parthkohli):

^ lol

Parth (parthkohli):

Thanks fellow agent >:D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!